Period of a SHM
A 470 g mass vibrates according to the equation x = 0.354 sin (15.37 t) where x is in meters and t is in seconds. Determine the period.
0.409 s
0.409 s
Approach
The general equation of a simple harmonic motion is given by x=Asin(2*pi*f*t) Different values can be read off by comparing the given equation with the general equation
Solution
Given the equation of motion is x = 0.354 sin (15.37 t) where x is in meters and t is in seconds. Comparing with the general equation of motion, 2 π f = 15.37. Now the period T = 1/f = 2 π/15.37 = 0.409 s.