## Period of a SHM

A 470 g mass vibrates according to the equation x = 0.354 sin (15.37 t) where x is in meters and t is in seconds. Determine the period.

**0.409 s**## **Approach**

The general equation of a simple harmonic motion is given by x=Asin(2*pi*f*t) Different values can be read off by comparing the given equation with the general equation

## **Solution**

Given the equation of motion is x = 0.354 sin (15.37 t) where x is in meters and t is in seconds. Comparing with the general equation of motion, 2 π f = 15.37. Now the period T = 1/f = 2 π/15.37 = 0.409 s.