## Car Accident

You are the juror of a case involving a drunken driver whose 1001.0 kg sports car ran into a stationary 1966.0 kg station wagon stopped at a red traffic light. The cars stuck together and slid with locked wheels for 11.0 m before coming to rest. The coefficient of sliding friction on the dry road was 0.8. Estimate the speed of the sports car when it hit the station wagon.

**8.71×101 mi/hr**

Estimate the instantaneous acceleration of the sports car during the actual collision if the colliding cars reach the same final speed after collapsing a combined total distance of 0.9 m.**-7.47×102 m/s^2**## Discussion

NEW

And I use the D that they give me in part 2 and not the D

in part one correct?

Just to explain the 2nd part for anyone else who decided to

finish this late... What you have to do is first use the

equation:

m1v1 + m2v2 = (m1+m2)v3

v1 is the answer you received from part 1 and v2 is 0, so

you get: m1v1/(m1+m2)=v3

Next, use the equation: a=(v3^2-v1^2)/2D

The D is the distance that is given in the second part.

The answer should be negative. Hope that helps.

And I use the D that they give me in part 2 and not the D

in part one correct?

**NEW****Re: Please help***Anonymous 11*Just to explain the 2nd part for anyone else who decided to

finish this late... What you have to do is first use the

equation:

m1v1 + m2v2 = (m1+m2)v3

v1 is the answer you received from part 1 and v2 is 0, so

you get: m1v1/(m1+m2)=v3

Next, use the equation: a=(v3^2-v1^2)/2D

The D is the distance that is given in the second part.

The answer should be negative. Hope that helps.