## Pulling a Cart

A horse pulls a cart with a force of 155.0 N at an angle of 28.0° with respect to the horizontal and moves along at a speed of 8.6 km/hr. How much work does the horse do in 10.5 min?

**206000 J**## Approach

The work done is on the cart is the force times the distance times the angle between the force and the distance, i.e., W = F d cos(θ).

## Solution

Given: Force F = 155.0 N and angle θ = 28.0°

The distance d can be calculated from the speed and the time it takes. d = vt = (8.6/3.6 m/s)(10.5·60 s) = 1505 m. So the work done is W = (155.0 N)×(1505 m)×cos(28.0°) = 206000 J.

The distance d can be calculated from the speed and the time it takes. d = vt = (8.6/3.6 m/s)(10.5·60 s) = 1505 m. So the work done is W = (155.0 N)×(1505 m)×cos(28.0°) = 206000 J.