## Medieval Castle

Assume you are a Medieval knight attacking a castle with a cannon. The ball leaves the cannon with a speed of 48.3 m/s. The barrel's angle with respect to the ground is 38.1°, and you make a perfect hit on the tyrant's chamber which is at the same level as the cannon's muzzle.

What is the time of flight of the cannon ball?

What is the time of flight of the cannon ball?

**6.08 s**## Disussion

*Anonymous 2*(Wed Jan 20 11:06:24 pm 2010 (EST))

how do you find the height the cannon ball reaches?

**NEW**

*Anonymous 3*(Thu Jan 21 05:23:06 pm 2010 (EST))

can someone point me in the right direction to start this?

**NEW**

know velocity and angle, so use the equation from 4.23 in

the book to find time to the top of the arc, then have to

double it.

**NEW**

the equation you would use to find ymax would be:

ymax= Vo*sin/g

Initial velocity times the sin of the angle made by the

ground and the projectile divided by gravity (9.8m/s^2)

sense the cannon lands at the same level it is projected

you can multiply the previous equation by two to get total

hang time.

**NEW**

*Anonymous 2*(Thu Jan 21 09:13:11 pm 2010 (EST))

that is exactly what i did but it isn't accepting my

answer..any suggestions?

**NEW**

You're trying to find the max height (ymax). Since you know

your angle (theta), you can obtain ymax by using sin(theta)

= ymax/initial velocity. However, you have to factor in the

force of gravity, so your final equation becomes:

Ymax = Initial velocity x [sin(theta)/9.8]

**NEW**

Oh, and then multiply the answer to what I just posted by

two, since you have to account for the descent of the

cannonball as well.

**NEW**

If someone could give another explanation to solve this that

would be great! I've tried the other equations and still am

not getting the correct answer

**NEW**

make sure your calculator is set to deg.