## Dropping a Payload

## Approach

A package dropped from a plane that is flying horizontal will have the same velocity in the x-direction (horizontal) as the plane. However, the initial velocity in the y-direction (vertical) is zero. The time for the package to drop to the island is determined by the vertical height only.

## Solution

In the y-direction:

initial velocity vy0 = 0

vertical height y0 = 93 m

acceleration a = -g

From... Y = Yo + (Vyo*t )-(1/2*g*t^2)

0 = 93m - 0*t -1/2(9.8m/s^2)t^2

solving for t = 4.36 s

initial velocity vy0 = 0

vertical height y0 = 93 m

acceleration a = -g

From... Y = Yo + (Vyo*t )-(1/2*g*t^2)

0 = 93m - 0*t -1/2(9.8m/s^2)t^2

solving for t = 4.36 s

## Part B

## Approach

The horizontal distance traveled is the speed along the horizontal (x) direction (which does not change since there is no accleration along x.) times the time it takes for the package to drop.

## Solution

Horizontal distance x = vx0 t = (155/3.6 m/s)(4.36 s) = 188 m.