CM of a Mallet
A mallet consists of a uniform cylindrical head of mass 2.00 kg and a diameter D = 0.070 m mounted on a uniform cylindrical handle of mass 0.488 kg and length L = 0.280 m, as shown in figure below.
If this mallet is tossed, spinning, into the air, how far above the bottom of the handle is the point that will follow a parabolic trajectory?
0.281 m
If this mallet is tossed, spinning, into the air, how far above the bottom of the handle is the point that will follow a parabolic trajectory?
0.281 m
Discussion
NEW
Anonymous 1
Can anyone help me for this problem?? I am completley lost
here!
NEW
Re:
To find the CM, use the equation CM=(m1*x1)+(m2*x2)/(m1+m2),
but x1 is half of the length of the handle and x2 is the
length of the handle plus the radius, not diameter, of the
head. The masses are both given. Hope this helps!
NEW
Help please
What are the units?
NEW
m
Anonymous 1
Can anyone help me for this problem?? I am completley lost
here!
NEW
Re:
To find the CM, use the equation CM=(m1*x1)+(m2*x2)/(m1+m2),
but x1 is half of the length of the handle and x2 is the
length of the handle plus the radius, not diameter, of the
head. The masses are both given. Hope this helps!
NEW
Help please
What are the units?
NEW
m