## Car in a Lake

A car misses a turn and sinks into a shallow lake to a depth of 8.7 m. If the area of the car door is 0.69 m2, what is the force exerted on the outside of the door by the water? Note: 1 atm = 101.325 kPa.

**1.29×105 N**

What is the force exerted on the inside of the door by the air, assuming the inside of the car is at atmospheric pressure? Think about what the occupant should do to get the door open.**6.99×104 N**## Discussion

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*Anonymous 1*

part 2 is the answer -ve ?

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**Re:**

nvm for prt 2 its just

P= 101000 Pa= 1 atm

A= (given in problem)

F=P*A

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*Anonymous 2*

How do we find the area for the lake?

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*Anonymous 2*

Can I get some help on part A? I found the pressure of the

water and multiplied it by the area of the car door, but

that's not the right answer.

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**part a**

find density of liquid

water=1000kg/m3

to find pressure of something in liquid=pgh

1000*9.8*h, dont forget about 1atm on top of water

so u add 101000 to pgh and the multiply by A

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**Re: part a**

*Anonymous 4*

So i did this and I after adding my answer (127400 +

101000) i get 228400 Pa * 0.58m^2 = 132472 N. I was

wondering do I have to do some sort of conversion because

it is not accepting my answer and I have tried to convert

to atm, kPa, torr then multiply that converted pressure by

the area but it is not working. Can someone help me out.

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**Re: Re: part a**

*Anonymous 4*

Never mind, i did the scientific notation wrong (E4 instead

of E5)

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units?

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**part 1**

i got 118404 for my answer but it's not accepting it, is there something else i

have to do?